sebuah tabung yang volumenya 1 liter

Diketahui:

Tabung space terdapat space lubang V equals 1 space liter equals 1 cross times 10 to the power of negative 3 end exponent space straight m cubed T subscript 1 equals 27 degree straight C equals 300 space straight K T subscript 2 equals 127 degree straight C equals 400 space straight K m subscript 1 equals m

Ditanya: fraction numerator capital delta m over denominator m subscript 1 end fraction equals... ?

Penyelesaian:

1. Menentukkan nilai dari m subscript 2

fraction numerator P subscript 1 V subscript 1 over denominator P subscript 2 V subscript 2 end fraction equals fraction numerator n subscript 1 R T subscript 1 over denominator n subscript 2 R T subscript 2 end fraction fraction numerator up diagonal strike P subscript 1.1 over denominator up diagonal strike P subscript 2 end strike. space 1 end fraction equals fraction numerator fraction numerator m subscript 1 over denominator M r end fraction up diagonal strike R 300 over denominator fraction numerator m subscript 2 over denominator M r end fraction up diagonal strike R space 400 end fraction 1 over 1 equals fraction numerator fraction numerator m subscript 1.300 over denominator M r end fraction over denominator fraction numerator m subscript 2.400 over denominator M r end fraction end fraction fraction numerator m subscript 2.400 over denominator M r end fraction equals fraction numerator m subscript 1.300 over denominator M r end fraction  m subscript 2.400. M r space equals m subscript 1.300 M r m subscript 2 space equals fraction numerator 300 m subscript 1 up diagonal strike M r end strike over denominator 400 up diagonal strike M r end strike end fraction m subscript 2 equals 3 over 4 m

m subscript 1 over m subscript 2 equals T subscript 2 over T subscript 1 m over m subscript 2 equals 400 over 300 m subscript 2 equals 3 over 4 m.

Maka, perbandingan antara massa gas yang keluar dari tabung dan massa awalnya adalah:

fraction numerator increment m over denominator m subscript 1 end fraction equals fraction numerator m subscript 1 minus m subscript 2 over denominator m subscript 1 end fraction fraction numerator increment m over denominator m subscript 1 end fraction equals fraction numerator m minus 3 over 4 m over denominator m end fraction fraction numerator increment m over denominator m subscript 1 end fraction equals fraction numerator 1 fourth up diagonal strike m over denominator up diagonal strike m end fraction fraction numerator increment m over denominator m subscript 1 end fraction equals 1 fourth

Dengan demikian, perbandingan antara massa gas yang keluar dari tabung dan massa awalnya adalah 1 : 4.

Oleh karena itu, jawaban yang benar adalah B. space space

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