luas permukaan gabungan tabung dan kerucut

Dari soal diketahui

r subscript tabung equals r subscript kerucut equals 14 divided by 2 equals 7 space cm t subscript tabung equals 12 space cm t subscript kerucut equals 36 minus 12 equals 24 space cm

Sebelumnya akan ditentukan panjang garis pelukis kerucut, dengan cara teorema phytagoras berikut.

table attributes columnalign right center left columnspacing 0px end attributes row s equals cell square root of t squared plus r squared end root end cell row blank equals cell square root of 24 squared plus 7 squared end root end cell row blank equals cell square root of 576 plus 49 end root end cell row blank equals cell square root of 625 end cell row blank equals cell 25 space cm end cell end table

Luas permukaan bangun tersebut dapat ditentukan dengan cara berikut.

table attributes columnalign right center left columnspacing 0px end attributes row cell straight L subscript permukaan end cell equals cell straight L subscript alas space tabung end subscript plus straight L subscript selimut space tabung end subscript plus straight L subscript selimut space kerucut end subscript space end cell row blank equals cell πr squared plus 2 πrt plus πrs end cell row blank equals cell 22 over 7 times 7 times 7 plus 2 times 22 over 7 times 7 times 12 plus 22 over 7 times 7 times 25 end cell row blank equals cell fraction numerator 22 over denominator up diagonal strike 7 end fraction times up diagonal strike 7 times 7 plus 2 times fraction numerator 22 over denominator up diagonal strike 7 end fraction times up diagonal strike 7 times 12 plus fraction numerator 22 over denominator up diagonal strike 7 end fraction times up diagonal strike 7 times 25 end cell row blank equals cell 22 times 7 plus 2 times 22 times 12 plus 22 times 25 end cell row blank equals cell 154 plus 528 plus 550 end cell row blank equals cell 1.232 space cm squared end cell end table

Jadi, jawaban yang tepat adalah D

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